Ten most important questions of Reasoning Analogy in missing numbers in various figures

Ten most Important questions of Reasoning Analogy of missing numbers have been discussed with their Solutions in an easy manners. These questions are very very important for competitive exams like SSC CGL , SSC CHSL And RRB NTPC Etc Because such types of problems are frequently asked in these exams.

 Problem #1  

Moving clock wise from top right number , Double the top right number to get bottom right number and add 2 to get bottom left number, now again double this number to get top left number in all the three figures .

Hence in  option (4)  24  is right answer

    Problem #2

Multiply  all the numbers which are on the corners of the given triangles to get the number which is on the centre of particular triangle.

In 1st triangle  multiply all the numbers on the corner of triangle

1 × 2 × 3 = 6

Again In 2nd  triangle  multiply all the numbers on the corner of triangle

2 × 5 × 3 = 30

Similarly In 3rd  triangle  multiply all the numbers on the corner of triangle

4 × 8 × 5 = 160

Hence in  option (3)  160  is right answer

WHAT IS THE NEXT TERMS IN THE SERIES.

Problem #3

If we add the top and bottom  numbers and the subtract from it the sum of left  and right  terms we shall get the middle number in all the figures.
in 1st figure

(3+7) - (2+5) = 10 - 7 = 3 ( Middle number in 1st figure) 
In 2nd figure

(9+9) - (7+8) =18 -15 = 3( Middle number in 2nd figure) 
In 3rd figure 

(8+8) - (6+6) = 16 -12 = 4( Middle number in 3rd figure) 

Hence in  option (2) 4 is right answer

Problem # 4

Multiply the top numbers and bottom numbers row wise the take the difference  of it .

In 1st figure 

( 5 × 6 ) - ( 3 × 8) = 30 - 24 = 6 ( Middle number in 1st figure) 

2nd figure

( 10 × 4 ) - ( 2 × 7 ) = 40 - 14 = 26 (Middle number in 2nd figure) 

3rd figure 

( 9 × 7 ) - ( 6 × 8 ) = 63 - 48 = 15 ( Middle number in 3rd figure) 

Hence in  option (2)  15  is right answer

Problem #5 

Cross multiply the numbers to get middle number in all the figures .

In 1st figure 

12 × 5 = 15 × 4 = 60 ( Middle number in 1st figure) 

In 2nd figure
3 × 14 = 6 × 7 = 42 ( Middle number in 1st figure)

In 3rd figure
26 × 3 = 13 × 6 = 78 ( Middle number in 1st figure)

Hence in  option (3)  78 is right answer

Problem #6 

Take cube roots of all the numbers which are on outer side 
 all the ellipse ( given figure ) and then add these numbers  to get middle number in the figure .

In 1st figure  cube roots of 1, 64, 27 and 8 are 1 , 4 , 3 and 2 respectively. 

Now add these numbers. i.e 1 + 4 + 3 +2 = 10

In 2nd figure  cube roots of 8, 125, 64 and 27  are 2 , 5 , 4 and 3 respectively. 

Now add these numbers. i.e 2 +5 + 4 +3 = 14

Similarly In 3rd figure  cube roots of  27 , 216 , 125 and 64 are 3 , 6 , 5 and 4 respectively. 

Now add these numbers. i.e 3 + 6 + 5 + 4 = 18

Hence in  option (4)  18  is right answer

Problem #7 

In all the figure add both numbers which are 2nd and 3rd rows then multiply this result with the number which is on the right side of given figure in the 1st row to get the number on the left side of 1st row of given figure.

In 1st figure 1 + 2 =》3 × 9 = 27

In 2nd figure  2 + 3  =》 5 × 7  = 35

In 3rd  figure  x + 4  =》 (x+4) × 4 = 36

 4x + 16 = 36

 4x = 36 - 16 = 20

x = 5

Hence in  option (3)  5  is right answer

Problem #8 

1st Figure

 From 1st figure we can see that lower number is thrice (3 times) of sum ( addition ) of both numbers which are on upper portion of figure i. e . 18 + 9 = 27 .

Now multiply it with 3 , we get 27 ×3  =81 , which is the lower number in 1st figure.

3rd Figure

And for third  figure add both the numbers 24 and 7 and then multiply  the sum with 3 like this 24 + 7 = 31 and 31 × 3 = 93

2nd  Figure

Similarly ?  in 2nd figure can be found by adding 23 and 8 and then Multiply  it with 3 as follows 

     23 + 8 = 31 × 3 = 93 , Hence 93 is the required number.

Hence in  option (3)  93  is right answer

Problem #9 

From 1st two  figures if we multiply top and bottom terms and then subtract  the result of product of left and right terms from it we shall get the number in the middle of the circles in both the given figures.

( 6 × 7 ) - ( 4 × 5 ) = 20 ( Middle Number in 1st Figure ) . 

( 9 × 7 ) - ( 6 × 3 ) = 45 ( Middle Number in 2nd Figure ). 

Similarly middle number of 3rd figure can be calculated as follows

( 8 × 8 ) - ( 4 × 6 ) = 40 ( Middle Number in 3rd Figure )

Hence in  option (3)  40  is right answer

Problem #10

If we add the left and right  numbers and the subtract from it the sum of top and bottom  terms we shall get the middle number in all the figures

( 5 + 6 ) - ( 4 + 7) = 0

( 7 + 6 ) - ( 8 + 4 ) = 1

similarly 3rd term can be calculated as follows

( 11 + 2 ) - ( 0 + 2 ) = 11

Hence in  option (3)  11  is right answer

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