Ten Most Important Reasoning questions with answers for competitive exams of series, box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams.
10 Reasoning questions with answers for competitive exams
PROBLEM 1
This reasoning problem consists of three figures and every figure have three numbers associated to it . Two numbers are on the upper line of each box and one number is at the bottom of the dark box. Look at last figure , it have ? in its centre . So the solution of this problem is to find the value of question mark using two numbers associated to it .
But the main problem is how to utilised these two numbers to get the value of question mark?
Now watch carefully the 1st two figures . Since these figures have some values of numbers in dark box .
Now we have to find or search the formula for these three numbers in each figure to utilised them in any possible way to get number in dark box .
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- The Number in each dark box in every figure is H C F ( Highest common Factor) of remaining two numbers.
Solution:- HCF of two numbers = 3rd number
H C F of 6 and 10 in 1st figure is 2 (The number in 1st figure of dark square).
H C F of 12 and 36 in 2nd figure is 12 (The number in 2nd figure of dark square).
H C F of 15 and 25 in 3rd figure is 5 (The number in 3rd figure of dark square).
Option (4)5 is correct option.
PROBLEM 2
This reasoning problem consists of three figures and every figure have three number associated to it . Two numbers are on the upper line of each box and one number is at the bottom of the dark box. Look at last figure , it have ? in its centre . So the solution of this problem is to find the value of question mark using two numbers associated to it .
But the main problem is how to utilised these two numbers to get the value of question mark?
Now watch carefully the 1st two figures . Since these figures have some values of numbers in dark box .
Now we have to find or search the formula for these three numbers in each figure to utilised them in any possible way to get number in dark box .
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- The Number in each dark box in every figure is L C M ( Lowest common Multiple) of remaining two numbers.
Solution:- LCM of two numbers = 3rd number
L C M of 6 and 10 in 1st figure is 30 (The number in 1st figure of dark square).
L C M of 12 and 36 in 2nd figure is 48 (The number in 2nd figure of dark square).
L C M of 5 and 7 in 3rd figure is 35 (The number in 3rd figure of dark square).
Option (2)35 is correct option
PROBLEM 3
This box problem consist of three rows and three columns. And we have to find the value of question mark after studying the pattern of all the numbers in this box.
Second column in every row is equal to the five time of division of 1st column with 3rd column in every row.
1st Row
5 × {28 ÷ 7} = 5 × 4 = 20 (Middle Number in 2nd column 1st row)
2nd Row
5 × {84 ÷ 12} = 5 × 7 = 35 (Middle Number in 2nd column 2nd row)
3rd Row
5 × {45 ÷ 9} = 5 × 5 = 25 (Middle Number in 2nd column 3rd row)
Option (D)25 is correct option.
PROBLEM 4
This box problem consist of three rows and four columns. And we have to find the value of question mark after studying the pattern of all the numbers in this box. Third row of every column is equal to the product of square root of 1st row and cube root of 2nd row .
Formula :- 3rd row = Square root of 1st row × Cube root of 2nd row
1st Column
√1 × ∛8 = 1 × 2 = 2
2nd Column
√4 × ∛27 = 2× 3 = 6
3rd Column
√16 × ∛64 = 4 × 4 = 16
4th Column
√36 × ∛343 = 6 × 7 = 42 = ? (The value of question mark)
Option (C)42 is correct option
PROBLEM 5
In Roman number system C , CC , CCC , D , DC are number which have values in decimal system as follows.
C = 100
CC = 200
CCC = 300
D = 500
DC = 600
So 100 , 200 , 300 , 400 , 500 and 600 are the numbers in series of 100 difference. Hence in Roman number system 400 can be written as CD.
Therefore
Option (1)CD is correct option.
PROBLEM 6
In any coding language sum of 10 and 10 has been written as 6, sum of 20 and 20 has been written as 12 . In the same coding language sum of 30 and 30 has also been written as 12. Then we have to find the value of sum of 0 and 0 ?
In the above reasoning problem it is not 10 + 10 , Actually to find its solution we have to think like this way that "each number is written in word and then its letters have been counted to find the sum of two given numbers".
TEN + TEN = 3 (Three letters in word TEN) + 3(Three letters in word TEN) = 6 (Sum of letters in both the words is SIX).
TWENTY + TWENTY = 6(Six letters in word TWENTY) + 6(Six letters in word TWENTY) = 12(Sum of letters in both the words is TWELVE).
THIRTY + THIRTY = 6(Six letters in word THIRTY) + 6(Six letters in word THIRTY) = 12 (Sum of letters in both the words is TWELVE).
ZERO + ZERO = 4(Four letters in word ZERO) + 6(Four letters in word ZERO) = 8 (Sum of letters in both the words is 8).
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PROBLEM 7
In these type of reasoning problems 2nd number will be obtained from 1st number either by using one mathematical operation/ set of mathematical operations or by using any mathematical operation/ set of mathematical operations to individual digits of 1st number. Same mathematical operation/ set of mathematical operations or formula will be used in 3rd number to get fourth number.
Formula :- (Half of Square of 1st number) = 2nd number
(Half of Square of 3rd number) = 4th number
2nd Number
18² ÷ 2 = 324 ÷ 2 = 162 (2nd Number)
4th Number
36² ÷ 3 = 1296 ÷ 2 =648 ( 4th Number)
Option (4)648 is correct option.
PROBLEM 8
In these types of reasoning problems 2nd number will be obtained from 1st number either by using one mathematical operation/ set of mathematical operations or by using any mathematical operation/ set of mathematical operations to individual digits of 1st number. Same mathematical operation/ set of mathematical operations or formula will be used in 3rd number to get fourth number.
Formula :- Product of two consecutive factors = Any number
1st Number = 4 × 5 = 20
2nd Number = 6 × 7 = 42
3rd Number = 8 × 9 = 72
4th Number = 10 × 11 = 110
Option (2)110 is correct option.
PROBLEM 9
This reasoning problem consists of three figures and every figure have three numbers associated to it . So the solution of this problem is to find the value of question mark using other two numbers associated to it .
But the problem is how to utilised these two numbers to get the value of this question mark?
Now we have to find or search the formula for these two numbers in each figure to utilised them in any possible way to get third number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Half of the product of two outer numbers in each triangle is equal to third number .
1st Triangle
( 2 × 3 ) ÷ 2 = 6 ÷ 2 = 3 (Middle number in 1st triangle )
2nd Triangle
2nd Triangle
( 4 × 5 ) ÷ 2 = 20 ÷ 2 = 10 (Middle number in 2nd triangle )
3rd Triangle
3rd Triangle
( 6 × 7 ) ÷ 2 = 42 ÷ 2 = 21(Middle number in 3rd triangle )
Option (4)21 is correct option.
PROBLEM 10
This reasoning problem consists of three figures and every figure have three numbers associated to it . So the solution of this problem is to find the value of question mark using other two numbers associated to it .
But the problem is how to utilised these two numbers to get the value of this question mark?
Now we have to find or search the formula for these two numbers in each figure to utilised them in any possible way to get third number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Sum of two numbers in each triangle is equal to sum of remaining number .
1st Triangle
( 8 + 4 ) = ( 3 + 9 ) = 12
2nd Triangle
( 4 + 7 ) = ( 6 + 5 ) = 11
3rd Triangle
( 5 + ? ) = ( 9 + 3 ) = 12
5 + ? = 12
? = 12 - 5
? = 7
Option (1)7 is correct option.
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Ten Most Important Reasoning questions with answers for competitive exams of series , box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions.
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