Ten Missing term in box reasoning , Reasoning questions with answer, box reasoning with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl , RRB NTPC, Group D and various Bank exams and many other similar exams.
Missing term in box reasoning questions with answers
Problem # 1
1st Box
2nd Box
5 × 2 = 6 + 4 =103 × 3 = 7 + 2 = 9 4 × 4 = 7 + 9 =16 (choose one of the option from given four whose digits's product should be 16)
3rd Box
1st Box
2nd Box
3rd Box
Problem # 3
Formula :-
1st Box
2nd Box
7 + 1 = 8(Digit in ten's place) , 6 + 1 = 7(Digit in unit's place) Hence Number in 2nd column will be 87.
3 + 1 = 4(Digit in ten's place) , 5 + 1 = 6(Digit in unit's place) Hence Number in 2nd column will be 46.
8 + 1 = 9(Digit in ten's place) , 0 + 1 = 1(Digit in unit's place) Hence Number in 2nd column will be 91.
3rd Box
7 + 1 = 8(Digit in ten's place) , 9 + 1 = 10(Digit in unit's place). Hence Number in 2nd column will be 810.
9 + 1 = 10(Digit in ten's place) , 9 + 1 = 10(Digit in unit's place). Hence Number in 2nd column will be 1010.
6 + 1 = 7(Digit in ten's place) , 5 + 1 = 6(Digit in unit's place) Hence Number in 2nd column will be 76.Hence correct option is (2)1010.
Problem # 4
Formula :-
Difference between the numbers in 1st and 2nd column is same in every row in all the three Boxes.
1st Box
3rd Box
2nd Box
Problem # 5
Formula :-
Sum of all the numbers in 1st column is 50 and Sum of all the numbers in 2nd column is 60 in all the three boxes. 1st Box
14 + 13 + 23 = 5018 + 15 + 27 = 60
1st Box
3rd Box
22 + 18 + 10 = 5020 + 16 + 24 = 60
2nd Box
16 + 13 + ? = 5024 + 15 + 21 = 60Hence ? = 50 - (16 +13) ? = 50 - 29? = 21
Hence correct option is (4)21.
Problem # 6
Formula :-
Sum of all the numbers in every row is 100.
1st Row
2nd Row
3rd Row
Problem # 7
Formula :-
1st Box
2nd Box
5 × 2 = 6 + 4 = 103 × 3 = 5 + 1 = 64 × 3 = 8 + 4 = 12
3rd Box
Formula :-
1st Box
5 × 7 = 35 Number in middle row opposite to 2nd column (1st box 2nd column )2nd Box
3rd Box
Problem # 9
Formula :-
1st Box
3 + 5 = 8 Number in middle row opposite to 1st column (1st box 1st column).
5 + 9 = 14 Number in middle row opposite to 1st column (2nd box 1st column).
8 + 9 = 17 Number in middle row opposite to 1st column (3rd box 1st column).
Hence correct option is (2)17.
Problem # 10
Product of both the digits in 1st column is equal to product of both the digits in 2nd column in every row and in every box .
1st Box
5 × 4 = 4 × 5 = 20(1st row 1st box).
1 × 2 = 2 × 1 = 2(2nd row 1st box).
4 × 3 = 2 × 6 = 12(3rd row 1st box).
2nd Box
3 × 4 = 6 × 2 = 12(1st row 2nd box).
3 × 3 = 1 × 9 = 9(2nd row 2nd box).
4 × 6 = 8 × 3 = 24(3rd row 2nd box).
3rd Box
4 × 4 = 8 × 2 = 16(1st row 3rd box).
6 × 4 = ? × ? = 24(2nd row 3rd box).
So out of four option only the product of both the digits in 4th option is equal to 24.
3 × 5 = 5 × 3 = 15(3rd row 3rd box).
Hence correct option is (4)38
Ten Missing term in box reasoning questions with answers box with solutions discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions regarding this post.
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