Ten most Missing number Reasoning SSC CGL questions and answers for competitive exams, reasoning questions with answers for bank exams, Reasoning tricks for competitive exams have been discussed in this article for upcoming competitive exams.
10 Most Important Reasoning Problems for competitive Exams
Question #1
 |
| Misiing Number |
Since the question mark is in the 3rd figure. So the value of question mark will be calculated with the help of remaining four numbers in the 3rd figure in the same way, the middle numbers have been calculated in 1st and 2nd figure with the help of remaining four numbers. This question mark value can be found by this method.
Formula:-
Sum of four numbers = Product of both the digits in middle number.
Since the question mark is in the 3rd figure. So the value of question mark will be calculated with the help of remaining four numbers in the figure in the same way, the middle numbers in 1st and 2nd figure can be calculated with the help of remaining four numbers around each figure. This question mark value can be found by following method.
Calculation:-
7 + 4 + 7 + 12 = 30 = 5 × 6 = Multiplication of 5 and 6 (Middle number in 1st figure )
15 + 7 + 12 + 8 = 42 = 6 × 7 = Multiplication of 6 and 7 (Middle number in 2nd figure )
11 + 18 + 5 + ? = ???? = 6 × 6 = Multiplication of 6 and 6(Middle number in 3rd figure )
⇒ 34 + ? = 36
⇒ ? = 36 - 34
⇒ ? = 2
Hence option (1)2 is correct.
Question #2
Since the question mark is in the 3rd figure. So the value of question mark will be calculated with the help of remaining four numbers in the figure in the same way, the middle numbers in 1st and 2nd figure can be calculated with the help of remaining four numbers around each figure. This question mark value can be found by this method.
1st Circle
8 + 4 + 3 + 1 = 16 (Greatest number in 1st circle)
or
16 - (8 + 4 + 3) = The number in the middle of circle
16 - 15 = The number in the middle of circle
1 = The number in the middle of circle
2nd Circle
4 + 3 + 5 + 8 = 20 (Greatest number in 2nd circle)
or
20 - (4 + 3 + 5) = The number in the middle of circle
20 - 12 = The number in the middle of circle
8 = The number in the middle of circle
3rd Circle
6 + 4 + 5 + ? = 18
⇒ 15 + ? = 18
⇒ ? = 18 - 15
⇒ ? = 3 (Greatest number in 3rd circle)
This will be the value of question mark.
or
18 - (6 + 4 + 5 ) = The number in the middle of circle
18 - 15 = The number in the middle of circle
3 = The number in the middle of circle
Hence option (1)3 is correct.
Question #3
Starting from 4th quadrant in anticlockwise direction , add one to the sum of squares of both the numbers in outer part of the quadrant to get the value of the number in the inner part of same quadrant.
4th Quadrant
(2 + 8)² + 1 = 10² + 1 = 100 + 1 = 101
1st Quadrant
(3 + 8)² + 1 = 11² + 1 = 121 + 1 = 122
2nd Quadrant
(7 + 1)² + 1 = 8² + 1 = 64 + 1 = 65
3rd Quadrant
(5 + 4)² + 1 = 9² + 1 = 81 + 1 = 82 (The value of question mark)
Hence option (1)82 is correct.
Question #4
Starting from 4th quadrant in anticlockwise direction , Subtract one from the sum of squares of both the numbers in outer part of the quadrant to get the value of the number in the inner part of same quadrant.
4th Quadrant
(2 + 8 )² - 1 = 10² + 1 = 100 - 1 = 99
1st Quadrant
(3 + 8)² - 1 = 11² + 1 = 121 - 1 = 120
2nd Quadrant
(7 + 1 )² - 1 = 8² + 1 = 64 - 1 = 63
3rd Quadrant
(5 + 4 )² - 1 = 9² + 1 = 81 - 1 = 80 (The value of question mark)
Hence option (2)80 is correct.
Question #5
1st Figure
63 + 34 + 8 = 105 (Greatest number in 1st figure)
or
105 - (63 + 34) = The number in the middle of 1st figure
105 - 97 = The number in the middle of 1st figure
8 = The number in the middle of 1st figure
2nd Figure
30 + 10 + 5 = 45 (Greatest number in 2nd figure)
or
45 - (30 + 10) = The number in the middle of 2nd figure
45 - 40 = The number in the middle of 2nd figure
5 = The number in the middle of 2nd figure
3rd Figure
31 + 62 + ? = 121 This implies ? = 28 (Greatest number in 3rd figure)
or
121 - (62 + 31) = The number in the middle of 3rd figure
121 - 93 = The number in the middle of 3rd figure
28 = The number in the question mark in 3rd figure
Hence option (4)28 is correct.
Also Reads these articles
Reasoning for competitive exams
Box and circle reasoning
Reasoning for bank exams
Ten Tricky logical reasoning
Box and circle reasoning
Reasoning for bank exams
Ten Tricky logical reasoning
Question #6
This circle has been divided into four quadrants and each quadrant is composed of three numbers . In each quadrant two numbers are in outer quadrant of the circle and one number is in the inner quadrant of the circle.
Starting from fourth quadrant in clockwise direction.
Formula : - Half of sum of the squares of both the numbers in outer sector is equal to inner sector.
4th Quadrant
( 8² + 6²)/2 = ( 64 + 36)/2 = 100/2 =50 (Number in the inner part of the circle in 4th quadrant )
3rd Quadrant
( 7² + 5²)/2 = ( 49 + 25)/2 = 74/2 = 37 (Number in the inner part of the circle in 3rd quadrant )
2nd Quadrant
( 10² + 8²)/2 = ( 100 + 64)/2 = 164/2 = 82 (Number in the inner part of the circle in 2nd quadrant )
1st Quadrant
( 9² + 11²)/2 = ( 81 + 121)/2 = 202/2 = 101 (Number in the inner part of the circle in 1st quadrant ).
And 101 will be the value of question mark.
Hence option (4)101 is correct.
Question #7
This circle has also been divided into four quadrants and each quadrant is composed of three numbers . In each quadrant two numbers are in outer sector of the circle and one number is in the inner sector of the circle.
Starting from 1st quadrant in clockwise direction.
Formula : - Sum of the squares of both the numbers in outer sector is equal to inner sector.
1st Quadrant
(3 + 5)² = (8)² = 64 (Number in the inner part of the circle in 1st quadrant )
2nd Quadrant
(5 + 4)² = (9)² = 81 (Number in the inner part of the circle in 2nd quadrant )
3rd Quadrant
(4 + 2)² = (6)² = 36 (Number in the inner part of the circle in 3rd quadrant )
4th Quadrant
(6 + 4)² = (10)² = 100 (Number in the inner part of the circle in 4th quadrant ).And 100 will be the value of question mark.
Question #8
This box problem consists of three rows and three columns. To find the value of question marks in 3rd column of 3rd row, we have to add 1st ,2nd and 3th columns since since in every column is same in every row.
Formula :- The sum of 1st three columns in every row is same .
7 + 8 + 15 = 30 ( 1st row)
9 + 20 + 1 = 30 (2nd row)
14 + 2 + ? = 30 ( Because sum of all the three digits in 3rd row must be equal to the sum in other two rows)
Hence 16 + ? = 30
⇒ ? = 30 - 16
⇒ ? = 14
Therefore the value of question mark is 14
Hence option (B)14 is correct.
Question #9
This box problem consists of four rows and four columns. To find the value of question marks in 3rd column of 3rd row, we have to divide the sum of 1st ,2nd and 3th rows with 4 to get the value of number in 4th row.
Formula :- The one fourth of the sum of 1st three rows in every column.
5 + 8 + 7 = 20 ÷ 4 = 5 ( 1st column in 4th row)
9 + 6 + 13 = 28 ÷ 4 = 7 (2nd column in 4th row)
(7 + 10 + 19) ÷ 4 = 36 ÷ 4 = 9 (4th column in 4th row)
(8 + 9 + ?) ÷ 4 = 8 (3rd column in 4th row)
⇒ 17 + ? = 8 × 4
⇒ ? = 32 - 17
⇒ ? = 15
Hence option (D)15 is correct.
Also Reads these articles
Question #10
This box problem consists of four rows and four columns. To find the value of question marks in 4th column of fourth row, we have to multiply 1st ,2nd and 3th rows at the same time and then add 10 to the result so obtained.
Formula :- Ten more than the product of 1st three rows in every column.
(5 × 6 × 7 ) + 10 = 210 + 10 = 220 (1st column in 4th row)
(6 × 5 × 4 ) + 10 = 120 + 10 = 130 (2nd column in 4th row)
(3 × 4 × 5 ) + 10 = 60 + 10 = 70 (3rd column in 4th row)
(8 × 7 × 6 ) + 10 = 336 + 10 = 346 (4th column in 4th row)
Hence option (B)346 is correct.
In this post I discussed Ten Missing number Reasoning SSC CGL all questions and answers . Comment your valuable suggestion for further improvement.
Also Read these posts on Reasoning
nice explanation
ReplyDelete