Twenty Questions of Number analogy with answer for competitive examinations and missing number in reasoning for competitive exams like Bank PO, Bank clerk, SSC CGL, ssc chsl, RRB NTPC , group D etc have been discussed in this post.

Twenty Questions of number analogy for competitive exams

In this reasoning problem 1st number (8) is associated to 28 with the help of any rule , with the help of same rule we have to associate 27 to a number out of four given options.

Formula:-

1st number is cube of a number and 2nd number more than one the cube of successive number of 1st number.

2³ , (2+1)³+1 ,3³ , (3+1)³ +1

2³ , 3³+1 ,3³ , 4³ +1

Hence 4³ + 1 = 64 + 1= 65

Option (4)65 is correct option.

In this reasoning problem 1st number (46) is associated to 2549 with the help of any rule , in the same rule we have to associate 23 to a number out of four given options.

Formula:-

Squares of successive digits of number on the left hand side = Number on the right hand side

(4+1)² = 5² = 25

(6+1)² = 7² = 49

Similarly (2+1)² = 3² = 9

(3+1)² = 4² = 16

Hence 916 will be the value of question mark .

Option (3)916 is correct option.

1st Method

In this reasoning problem 1st number (37) is associated to 23 with the help of any rule , in the same rule we have to associate 19 to a number out of four given options.

Look carefully the given numbers consists of two digits. These two digits can be utilised with the help a formula given below.

Formula :-

1st Number - 2nd Number = 14

37 - 23 = 14

19 - ? = 14

? = 19 - 14

? = 5

Option (4)5 is correct option.

2nd Method

All the three given numbers are prime numbers, so the value of question mark must be a prime number. And out of all the four options given only fourth option having value 5 is prime number.

Hence Option (4)5 is correct option.

In this reasoning problem 1st number 29 is associated to 71 with the help of any rule , in the same rule we have to associate 79 to a number out of four given options.

1st Number

29 × 2 = 58 Now add sum of both the digits of 58 to 58 to get 2nd number.

58 + (5+8) = 58 + 13 = 71

3rd Number

79 × 2 = 158 Now add sum of all the digits of 158 to 158 to get 4th number.

158 + (1+5+8) = 158 + 14 = 172

Hence Option (3)172 is correct option.

In this reasoning problem 1st number (79) is associated to 47 with the help of some rule , With the help of same rule we have to associate 75 to a number out of four given option. Also in this problem all the numbers consists of two digits. These two digits can be used to find the value of question mark with the help a formula given below.

Formula :-

( 1st digits × 2nd digit } - {1st digits + 2nd digit}.

{ 9 × 7 } - { 9 + 7 } = 63 - 16 = 47

{ 7 × 5 } - { 7 + 5 } = 35 - 12 = 23 = ? ( The value of question mark )

Option (2)23 is correct option.

In this reasoning problem 1st number 87 is associated to 414 with the help of some rule , With the help of same rule we have to associate 62 to a number out of four given option. Also in this problem all the numbers consists of three digits. These three digits can be used to find the value of question mark with the help a formula given below.

Formula :-

{(1st digit of 1st Number) ÷ 2} and {(2nd digit of 1st Number) × 2 } = 2nd Number

{ 8 ÷2 } and { 7× 2 } = 4 and 14 = 414 = 2nd Number

{ 6 ÷2 } and { 2× 2 } = 3 and 4 = 34 = 4th Number = ? ( The value of question mark )

Option (2)34 is correct option.

Formula :-

{1st digit × 2nd digit } + { 3rd digit × 4th digit } = 2nd Number.

1st Number

(2 × 5) + (7 × 3) = 10 + 21 = 31 = 2nd Number

2nd Number

(4 × 6) + (2 × 9) = 24 + 18 = 42 = 4th Number

Option (3)42 is correct option.

In this reasoning problem 1st number 144 is associated to 23 with the help of some rule , With the help of same rule we have to associate 196 to a number out of four given option. Also in this problem all the numbers consists of three digits. These three digits can be used to find the value of question mark with the help a formula given below.

Formula :-

{2 × Square Root (1st Number) }- 1 = 2nd Number

{2 × √144} - 1 = {2 × 12} - 1 = 24 - 1 = 23 = 2nd Number

{2 × √196} - 1 = {2 × 14} - 1 = 28 - 1 = 27 = 4th Number = ? ( The value of question mark )

Option (1)27 is correct option

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Squaring both digits of 1st number separately, now Interchanging both digits of numbers obtained after Squaring. Now combining these numbers to form the value of 2nd number.

1st Number = 43

4² = 16 = 61(After Interchanging both digits)

3² = 09 = 90(After Interchanging both digits)

Now combining both the squares as 6346 = 2nd number.

3rd Number = 68

6² = 36 = 63(After Interchanging both digits)

8² = 64 = 46(After Interchanging both digits)

Now combining both the squares as 6346= 4th number.

Option (3)6346 is correct option

Prime factors of 6 = 2,3 and multiplication of 2 and 3 = 6

Prime factors of 15 = 3,5 and multiplication of 3 and 5 = 15

Prime factors of 35 = 5,7 and multiplication of 5 and 7 = 35

Similarly

Prime factors of ? = 7,11 and multiplication of 7 and 11 = 77.

Option (1)77 is correct option

Usually in these types of reasoning problem 1st number is associated to 2nd number with the help of some rule . Similarly 3rd number is associated to 4th number with the help of same rule.

But in this reasoning problem all the four numbers are written sequence wise . It Means 2nd term will be found from 1st term, 3rd term will be found from 2nd term and after applying same formula or rule 4th term will be calculated from 3rd term.

Formula :-

nth Term = {(n+1) × Previous Term} + 4

1st term = 2

2nd term = (8 × 3) + 4 = 24 + 4 = 24

3rd term = (28 × 4) + 4 = 112 + 4 = 116

4th term = (116 × 5) + 4 = 580 + 4 = 584

Option (4) 584 is correct option

In this reasoning problem 1st number (11) is associated to 38 with the help of any rule , in the same rule we have to associate 13 to a number out of four given option.

Look carefully the given numbers consists of two digits. These three digits can be utilised with the help a formula given below.

Formula :-

(1st Number × 4) - 6 = 2nd Number

{11 × 4 } - 6 = 44 - 6 = 44 = 2nd Number

{13 × 4 } - 6 = 52 - 6 = 46 - 4th Number

Option (2)46 is correct option

Interchanging position of unit place and ten's place of given 1st number 34 . we shall get 43, Now taking the squares of each digit of given number 43 separately. we shall have 16 and 9. Now combining these squares to get 2nd numbers which is 169.

Similarly interchanging position of unit place and ten's place of 3rd number 23 . we shall get 32. Now taking the squares of each digit of given number 32 separately. we shall have 9 and 4. Now combining these squares to get 4th numbers which is 94.

Option (4)94 is correct option

In this reasoning problem 1st number (0) is associated to 6 with the help of some rule , With the help of same rule we have to associate 24 to a number out of four given option.

Formula :-

nth Term = n³ - n

0 = 1³ -1 = 1st number

6 = 2³ -2 = 2nd number

24 = 3³ -3 = 3rd number

? = 4³ - 4 = 64 - 4 = 60 = 4th number

Option (4)60 is correct option

In this reasoning problem 1st number (49) is associated to 23 with the help of some rule , With the help of same rule we have to associate 91 to a number out of four given option. Also in this problem all the numbers consists of two digits. These two digits can be used to find the value of question mark with the help a formula given below.

Formula :-

{Square Root of 1st digits and Square Root of 2nd digit } of 1st Number = 2nd Number

√4 and √9 = 2 and 3 = 23 = 2nd Number

√9 and √1 = 3 and 1 = 31 = 4th Number= ? ( The value of question mark )

Option (1)31 is correct option.

In this reasoning problem 1st number (48) is associated to 1664 with the help of some rule , With the help of same rule we have to associate 27 to a number out of four given option. Also in this problem all the numbers consists of two digits. These two digits can be used to find the value of question mark with the help a formula given below.

Formula :-

{Square of 1st digits and Square of 2nd digit } of 1st Number = 2nd Number

1st Number 48

4² and 8² = 16 and 64

Hence after combining we have 1664 = 2nd Number

2nd Number 27

2 = 4 and and 7² =49.

Hence after combining we have 449 = 4th Number= ? ( The value of question mark )

Option (1)449 is correct option.

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Difference of 2nd number and 1st number = 20

24 - 4 = 20

Similarly difference of 4th number and 3rd number must be 20

? - 17 = 20

? = 20 + 17

? = 37

Option (4)37 is correct option.

In this reasoning problem 1st number (49) is associated to 6 with the help of some rule , With the help of same rule we have to associate 82 to a number out of four given option. Also in this problem all the numbers consists of two digits. These two digits can be used to find the value of question mark with the help a formula given below.

Formula :-

Square Root of( 1st digits × 2nd digit } of 1st Number = 2nd Number

√(4 *9) = √(36) = 6 = 2nd Number

√(8 *2) = √(16) = 4 = 4th Number = ? ( The value of question mark )

Option (2)4 is correct option.

In this reasoning problem 1st number 24 is associated to 16 with the help of any rule , in the same rule we have to associate 52 to a number out of four given option.

Formula = 2× (Sum of both digits of 1st number) = 2nd Number

1st Number 24

2×{ 2 × 4 } = 2 × 8 = 16 = 2nd number

3rd Number 52

2×{ 5 × 2 } = 2 × 10 = 20 = 4th number

Option (4)20 is correct option.

In this reasoning problem 1st number 2 is associated to 32 with the help of any rule , in the same rule we have to associate 3 to a number out of four given option.

1st Number 2

2⁵ = 2 × 2 × 2 × 2 × 2 = 32 = 2nd number

3rd Number 52

3⁵ = 3 × 3 × 3 × 3 × 3 = 243 = 4th number.

Option (2)243 is correct option.

Conclusion

Comment your valuable suggestion regarding the post most important Reasoning questions with answers which includes reasoning for competitive exams, circle problems, box problems, circle problems and triangles problems for competitive exams like SSC CGL ,SSC CHSL ,CPO ,Bank exams and RRB NTPC etc which were explained in this post.