Most important Reasoning questions with answers which includes circle problems, box problems, circle problems, triangles problems  for competitive exams like SSC CGL ,SSC CHSL ,CPO ,Bank exams and RRB NTPC etc have been explained in this post. 

Ten Important Reasoning questions with answers for competitive exams

 

Problem # 1

SSC CGL Reasoning 

This reasoning problem consists of two figures and every figure have five numbers associated to it . So the solution of this problem is to find the value of question mark using other four numbers associated to it . 

But the major problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st figures . Since this figure have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in 1st figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula :- The difference of  product of both the numbers in upper row and product of both the numbers in lower row is equal to middle number in every figure.

( 11 × 12 ) - ( 6 × 9 ) = 132 - 54 = 78 (Middle number in 1st figure )

( 14 × 10 ) - ( 7 × 8 ) = 140 - 56 = 84 (Middle number in 2nd figure)

Option (1)84 is correct option

Problem # 2

SSC CGL Reasoning 

This reasoning problem consists of only one figure and this figure have eight numbers associated to it . So the solution of this problem is to find the value of question mark using other numbers associated to it . 

But the major problem is how to utilised these four numbers to get the value of this question mark?

Formula :- Sum of  twice of any number in the inner circle and its adjoining number taken in clockwise order is equal to number in the outer circle.

( 3 × 2 ) + 4 (number when moving from  3 clockwise ) = 6 + 4 = 10 ( Number in the outer circle ) 

( 4 × 2 ) + 6 (number when moving from 3 clockwise ) = 8 + 6 = 14 ( Number in the outer circle ) 

( 6 × 2 ) + 8 (number when moving from  3 clockwise ) = 12 + 8 = 20 ( Number in the outer circle )

( 8 × 2 ) + 3  (number when moving from 3 clockwise ) = 16 + 3 = 19 ( Number in the outer circle )

Option (1)19 is correct option

Problem # 3

SSC CGL Reasoning 

This reasoning problem consists of three figures and every figure have three numbers associated to it . So the solution of this problem is to find the value of question mark using other two numbers associated to it . 

          But the problem is how to utilised these two numbers to get the value of this question mark?

          Now we have to find or search the  formula for these two numbers in each figure to utilised them in any possible way to get third number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula :- The sum of  two numbers which are on the perpendicular lines is equal to third number of triangle in every figure.

( 13 + 19 ) ÷ 8 = 32 ÷ 8 = 4 ( 3rd number in 1st triangle ) 

( 71 + 9 ) ÷ 8 = 80 ÷ 8 =  10 ( 3rd number in 1st triangle ) 

( 128 + 32 ) ÷ 8 = 160  ÷ 8 = 20 ( 3rd number in 1st triangle ) 

Option (2)20  is correct option

Problem # 4

SSC CGL Reasoning 

This reasoning problem consists of three figures and every figure have five numbers associated to it . So the solution of this problem is to find the value of question mark using other four numbers associated to it . 

But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. The same formula will be applicable to third figure to find out the value of question mark.

Formula :- The sum of  product of left & right and sum of lower and upper numbers in each figure is equal to middle number in every figure.

( 6 × 7 ) + ( 8 + 4 ) = 42 + 12 = 54 ( Middle number in 1st figure ) . 

( 8 × 4 ) + ( 12 + 7 ) = 32 + 19 = 51 ( Middle number in 2nd figure ) . 

( 9 × 5 ) + ( 14 + 9 ) = 45 + 23 = 68 ( Middle number in 3rd figure ) . 

Option (2)68 is correct option

Problem # 5

SSC CGL Reasoning 

This reasoning problem consists of three figures and every figure have six numbers associated to it . So the solution of this problem is to find the value of question mark using other five numbers associated to it . 

But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . Since these figures have some values in middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula :- The product of top three numbers in any figure is equal to product of other three numbers in every figure.

(4 × 3 × 5 ) = 60 =  ( 20 × 3 × 1 )  ( Multiplication of top three numbers is equal to multiplication  of bottom three numbers ) . 

 (2 × 4 × 5 )  = 40 =  ( 10 × 2 × 2 )  ( Multiplication of top three numbers is equal to multiplication  of bottom three numbers ) . 

( 8 × 6 × 1 ) = 48 =  ( ? × 3 × 4 ) =  Multiplication of top three numbers is equal to multiplication  of bottom three numbers ) . 

? = 48 ÷  12

? = 4

Option (1)4 is correct option

Problem # 6

SSC CGL Reasoning 

In these types of reasoning problems 2nd number will be obtained from 1st number either by using one mathematical operation/ set of mathematical operations or by using any mathematical operation/ set of mathematical operations to individual digits of 1st number. Same  mathematical operation/ set of mathematical operations  or formula will be used in 3rd number to get fourth number.

Formula :-  (1st digit  ×2nd digit) ÷  middle digit  = 2nd number     

( 5  × 6  ) ÷ 2 = 30 ÷ 2 = 15

( 8  ×  3 ) ÷ 3 = 24 ÷ 3 = 8

Option (1)8 is correct option

Problem # 7

SSC CGL Reasoning 

In these types of reasoning problems 2nd number will be obtained from 1st number either by using one mathematical operation/ set of mathematical operations or by using any mathematical operation/ set of mathematical operations to individual digits of 1st number. Same  mathematical operation/ set of mathematical operations  or formula will be used in 3rd number to get fourth number.

Formula :-  Reversing the digits of square root of 1st number = 2nd number

 (√289 )= 17  ⇔ 71 (After reversing the order of digits ) 

√ (144 )= 12 ⇔ 21 (After reversing the order of digits ) 

Option (3)21 is correct option

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Problem # 8

SSC CGL Reasoning 

In these type of reasoning problems 2nd number will be obtained from 1st number either by using one mathematical operation/ set of mathematical operations or by using any mathematical operation/ set of mathematical operations to individual digits of 1st number. Same  mathematical operation/ set of mathematical operations  or formula will be used in 3rd number to get fourth number.

Formula :-  1st digit ^  2nd digit =  2nd number

Taking 1st digit as base and and digit as power then after expansion we have 

2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64 

3⁵ = 3 × 3 × 3 × 3 × 3 = 243

Option (1)243 is correct option

Problem # 9

SSC CGL Reasoning 

This reasoning problem consists of only one figure and this figure have eight numbers associated to it . So the solution of this problem is to find the value of question mark using other numbers associated to it . 

But the major problem is how to utilised these four numbers to get the value of this question mark?

Formula :- ( Any number   × Opposite of number already chosen ) + 1 = 61

(10 × 6) +1 = 60 +1 = 61(Middle number)

 (15 × 4) +1 = 60 +1 = 61(Middle number)

(5 × ? ) +1 = 60 +1 = 61(Middle number)

 (5 × ? ) +1 = 61

 (5 × ? )  = 60

 ?   = 60 ÷ 5

?  = 12

Option (2)12 is correct option

Problem # 10

SSC CGL Reasoning 

This reasoning problem consists of only one figure and this figure have eight numbers associated to it . So the solution of this problem is to find the value of question mark using other numbers associated to it . 

But the major problem is how to utilised these four numbers to get the value of this question mark?

Formula :- ( Any number   + Opposite of number already chosen ) + 13 = 71

(23 + 35 ) + 13 = 58 + 13 = 71(Middle number)

(41 + 17 ) + 13 = 58 + 13 = 71(Middle number)

 (46 + ? ) + 13 =   71(Middle number)

46 + ?  =   71 - 13

 46 + ? =   58

 ? = 58 - 46

? = 12

Option (2)12 is correct option. 

In this post I discussed Ten Tricky logical reasoning questions+answers , Latest reasoning questions with answers  . Comment your valuable suggestion for further improvement.

Read More

Ten important problems of reasoning with answers ,Reasoning questions with answers

Ten important problems of reasoning with answers , Reasoning of figure problems with answers which includes box problems for competitive exams like SSC CGL ,SSC CHSL ,CPO ,Bank exams and RRB NTPC etc have been explained in this post.

Ten Figure problems in reasoning with answers for competitive exams

Problem #1

This reasoning problem consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula :- The middle Number in each figure is one tenth of product of remaining numbers. 

Solution:-

 ( 4 × 5 × 7 × 6 ) ÷ 10 = 840 ÷ 10 = 84 ( Middle number in 1st figure).

 (2 × 8 × 4 × 5 ) ÷ 10 = 320 ÷ 10 = 32 ( Middle number in 2nd figure).

(5 × 6 × 9 × 2 )÷ 10 = 540 ÷ 10 = 54 ( Middle number in 3rd figure).

 Option (1) 54 is correct option 

Problem #2

This reasoning problem also consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it. 

          But the main problem is how to use these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula:-:- The middle Number in each figure is two less than the sum of remaining numbers. 

Solution:-

(4 + 5 + 7 + 6 ) - 2 = 22 - 2 = 20 ( Middle number in 1st figure).

(2 + 8 + 4 + 7 ) - 2 = 21 - 2 = 19 ( Middle number in 2nd figure).

(5 + 6 + 9 + 8 ) - 2 = 28 - 2 = 26 ( Middle number in 3rd figure),

Option (4) 26 is correct option.

Problem #3

This reasoning problem also have three figures and every figure have five number attached to it . Four numbers are at the corner of each figure and one number is at the middle of the same figure.             Since last figure have question mark in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula:- [{Left number × Top most number } + Right number ] - bottom number.

Solution:- 

 {(4 × 5) + 7 }- 20 = ( 20 + 7 ) - 20 = 27 - 20 = 7 ( Middle number in 1st figure) . 

 {(2 × 8 ) + 4} - 12 = ( 16 + 4 ) - 12 = 20 - 12 = 8 ( Middle number in 2nd figure). 

{(4 × 12 ) + 12} - 51 = ( 48 + 12 ) - 51 = 60 - 51 = 9 ( Middle number in 3rd figure). 

Option (2)9 is correct option.

Problem #4

This reasoning problem also have three figures and every figure have five number attached to it . Four numbers are at the corner of each figure and one number is at the middle of the same figure.

           Since 2nd figure have question mark in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st and 3rd figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to 2nd figure to find out the value of question mark.

Formula:-[{Left number × Top most number } + Right number ] - bottom number.

Solution:-

{(4 × 5 ) + 7 } - 16 = ( 20 + 7 ) - 16 = 27 - 16 = 11 ( Middle number in 1st figure). 

 {(4 × 12 ) + 1} - 33 = ( 48 + 1 ) - 33 = 49 - 33 = 16 ( Middle number in 3rd figure) .

{(2 × 8 ) + 3} - 12 = ( 16 + 3 ) - 12 = 19 - 12 = 7 ( Middle number in 2nd figure) . The value of question mark.  

Option (4)7 is correct option.

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Problem #5

This reasoning problem also have three figures and every figure have five number attached to it . Four numbers are at the corner of each figure and one number is at the middle of the same figure.             Since last figure have question mark in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          But the biggest problem is how to utilised these four numbers to get the value of this question mark?

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula:-   Add 1 to all the numbers in upper rows of each figure  to multiply the number opposite to it.

Solution:-

( 7 + 1) × 5 = ( 9 + 1) × 5 = 40 (Middle number in 1st figure ) . 

( 17 + 1) × 3 = ( 8 + 1) × 6 = 54 (Middle number in 2nd figure ). 

( 10 + 1) × 6 = ( 21 + 1) × 3 = 66 (Middle number in 3rd figure ). 

Option (4)66  is correct option

Problem #6

This reasoning problem also have three figures and every figure have five number attached to it . Four numbers are at the corner of each figure and one number is at the middle of the same figure. Since last figure have question mark in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula:-   Add 1 to all the numbers of each figure  to multiply the number opposite to it.

Solution:-

( 9 +1  ) × ( 3 + 1 ) = ( 9 + 1 ) × ( 3 + 1 ) =  10  × 4  = 40 ( Middle number in 1st figure ) . 

( 26 +1 ) × ( 1 + 1 ) = ( 8 + 1 ) × ( 5 + 1 ) = 27 × 2 = 40 ( Middle number in 2nd figure ). 

( 15 + 1  ) × ( 2 + 1 ) = ( 3 + 1 ) × ( 11 + 1 ) =  16  × 3 = 48 ( Middle number in 3rd figure). 

Option (3)48 is correct option

Problem #7

This reasoning problem also have three figures and every figure have five number attached to it . Four numbers are at the corner of each figure and one number is at the middle of the same figure.             Since last figure have question mark in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it . 

          Now watch carefully the 1st two figures . since these figures have some values of middle numbers. 

          Now we have to find or search the  formula for these four numbers in each figure to utilised them in any possible way to get middle or central number. 

         The same formula will be applicable to third figure to find out the value of question mark.

Formula:-  Product of both numbers in upper lines - Product of both numbers in lower lines   ⇔ Reverse order of both digits to get Middle number 

Solution:-

( 8  × 6 ) - ( 3 × 4 )  = 48 - 12 =  36  ⇔ 63 

( 7  × 6 ) - ( 5 × 6 )  = 42 - 30 =  12  ⇔ 21

( 5 × 7 ) - ( 9 × 2 ) = 35 - 18 = 17 ⇔ 71 

Option (1)71 is correct option

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Problem #8

This problem consists of two figures . Each figure have three numbers. In 1st figure a number in the last row have been written using other two numbers given in same figure with the help of any mathematical operation. This mathematical operation may be addition, subtraction,multiplication, division, combinations of any two operations or any other two or three operations.

Formula:- Number in Lower row = { Number in upper row - Number in middle row } × 2.

Twice the difference of two numbers in upper and middle row is equal to number in lower row.

(486 - 361 ) × 2 =  125 × 2 = 250

(395 - 279 ) × 2 =  116  × 2 = 232

Option (3)232 is correct option

Problem #9

This problem consists of two figures . Each figure have three numbers. In 1st figure a number in the last row have been written using other two numbers given in same figure with the help of any mathematical operation. This mathematical operation may be addition, subtraction,multiplication, division, combinations of any two operations or any other two or three operations.

Formula:- Number in Lower row = { Number in middle row - Number in upper row } × 6.

Six times the difference of two numbers in middle and upper row is equal to number in lower row.

( 555 - 444 ) × 6 = 111 × 6 = 666

( 765 - 543 ) × 6 = 222 × 6 = 1332

Option (4)1332 is correct option

Problem #10

This problem also consists of two figures . Each figure have three numbers. In 1st figure given number in the last row have been written using other two numbers given in same figure with the help of any mathematical operation. This mathematical operation may be addition, subtraction, multiplication, division, combinations of any two operations or any other two or three operations.

Formula:- Number in Lower row = Reversing the order of digits of the number of { Number in upper row - Number in middle row }.

Reverse the the digits of number obtained for difference of two numbers in upper and middle row is equal to number in lower row.

( 597 - 276 )  = 291 ⇔  192 (After reversing the digits of 291)

( 683 - 436 )  = 147 ⇔  741 (After reversing the digits of 741)

Option (3)741 is correct option

In this post I discussed Ten Tricky logical reasoning questions+answers , Latest reasoning questions with answers  . Comment your valuable suggestion for further improvement.

Read More

Maths Reasoning questions with answers for competitive exams

Ten most important reasoning questions with answers for competitive exams, maths reasoning questions, reasoning questions with answers for bank exams, Reasoning tricks for competitive exams have been discussed in this article for upcoming competitive exams. 

Ten most important maths reasoning questions for competitive exams.

Question #1

Reasoning questions 

This box problem consists of four rows and five columns. To find the value of question marks in fifth column of fourth row we have to combine two columns at a time and then take the difference of combination two other rows. 

Formula :-

 The difference of product of 1st and 4th column and sum of 2nd and 3rd column. 

(Number in 1st column × Number in 4th column ) - (Number in 2nd column + Number in 3rd column) = Number in 5th column

( 4 × 2 ) - ( 5 + 3 ) = 8 - 8 = 0 (1st row 4th column) 

( 7 × 4 ) - ( 3 + 4 ) = 28 - 7 = 21(2nd row 4th column) 

( 6 × 5 ) - ( 4 + 4 ) = 30 - 8 = 22(3rd row 4th column) 

( 9 × 5 ) - ( 6 + 5 ) = 45 - 11 =  34 = ? (The value of question mark) 

Option (2)34 is correct option.

 

Question #2

Since the question mark is in the middle of 3rd figure. So the value of question mark will be calculated with the help of remaining four numbers around this figure in the same way, the middle numbers in 1st and 2nd figure can be calculated with the help of remaining four numbers around each figure. This question mark value can be found by two methods. 

1st Method

( 52 - 41 ) + 5 = 11 + 5 = 16 ( Middle number in 1st figure ) 

( 92 - 85 ) + 5 = 7 + 5 = 12 ( Middle number in 2nd figure ) 

( 126 -  113 ) + 5 = 13 + 5 = 18 ( Middle number in 3rd figure ) 

Option (3)18 is correct option

2nd Method

[(4 + 2) - (5+ 1) + 16]= (6 - 6) + 16 = 0 + 16 = 16 (Middle number in 1st figure ) 

[(8 + 2) - (9 + 5) + 16]= (10 - 14) + 16 = -4 + 16 = 12 (Middle number in 2nd figure ) 

[(11+ 6 ) - (12+ 3) + 16]= (17 - 15) + 16 = 2 + 16 = 18 (Middle number in 3rd figure ) 

Option (3)18 is correct option.

Question #3

This box problem consists of four rows and three columns. To find the value of question marks in 2nd column of fourth row, we have to combine three rows at the same time. 

Formula :- 

The sum of cube of Numbers in 1st, 2nd and 3th rows is equal to Number in 4th row. 

( Cube of Number in 1st row   ) + ( Cube of Number in 2nd row  ) (Cube of Number in 3rd row )  = Number in 4th row

2³ + 1³ + 3³ = 8 + 1 + 27 = 36 (4th row 1st column) 

0³ + 4³ + 3³ = 0 + 64 + 27 = 91 (4th row 3rd column) 

4³ + 2³ + 1³ = 64 + 8 + 1 = 73 = ? (4th row 2nd column) 

Option (D)73  is correct option.

Question #4

This box problem also consists of four rows and three columns. To find the value of question marks in 4th row of 3rd column we have to combine three rows at the same time. 

Formula :- 

Sum of Product of hundred times of number in 2nd row and product of numbers in 1st and 3th rows is equal to Number in 4th row. 

100 × ( Number in 2nd row ) + ( Number in 1st row  ) ×  ( Number in 3rd row )  = Number in 4th row

(5 × 100) + ( 7 × 10 ) = 500 + 70 =  570 (4th row 1st column) 

(3 × 100) + ( 8 × 11 ) = 300 + 88 = 388 (4th row 2nd column) 

(1 × 100) + ( 2 × 9 ) = 100 + 18 = 118 (The value of question mark) 

Option (B)118 is correct option.

Question #5

Starting from 1 and moving in such a way that all the numbers must be written in increasing order as written in the following line as 

1 , 5 , 13  ,29  , 61 , 125 , ? 

Now we have to think the formula for the numbers , which is 3 more than the twice of previous number. 

Formula :-

Any number = ( 2 × previous number ) + 3.

(1 × 2 ) + 3 = 2 + 3 = 5

(5 × 2 ) + 3 = 10 + 3 = 13

(13 × 2 ) + 3 = 26 + 3 = 29

(29 × 2 ) + 3 = 58 + 3 = 61

(61 × 2 ) + 3 = 122 + 3 = 125

(125 × 2 ) + 3 = 250 + 3 = 253 = ? ( The value of question mark ) . 

Option (3)253  is correct option.

Question #6

Starting from 1 and moving in such a way that all the numbers must be written in increasing order as written in the following line as 

1 , 3 , 9 ,31 , 129 , 651 , ? 

Formula :-

Any number = ( 2 × previous number ) + 3.

(1 × 1 ) + 2 = 1 + 2 = 3

(3 × 2 ) + 3 = 6 + 3 = 9

(9 × 3 ) + 4 = 27 + 4 = 31

(31 × 4 ) + 5 = 124 + 5 = 129

(129 × 5 ) + 6 = 645 + 6 = 651

(651 × 6 ) + 7 = 3906 + 7 = 3913 = ? 

Option (1)3913 is correct option.

Question #7

This box problem also consists of four rows and three columns. To find the value of question marks in 4th row of 3rd column we have to combine three rows at the same time. 

Formula :-

 The  product of Numbers in 1st, 2nd and 3th rows is equal to Number in 4th row. 

2 × 4 × 5 = 40 (4th row 1st column) 

3 × 7 × 2 = 42 (4th row 2nd column) 

4 × 6 × 9 = 216 ( The value of question mark)

Option (B)216 is correct option,

Question #8

This box problem consists of three rows and three columns. To find the value of question marks in 3rd row of 3rd column we have to combine 1st two rows at the same time with the help of any or combination of mathematical operations. 

Formula :-

 The  square of half of the sum of numbers in 1st and 2nd rows in any particular column is equal to Number in 3rd row. 

[(25 + 15) ÷ 2 ]² = [ 40 ÷ 2 ]² =  [ 20 ]² = 400

[(16 + 10) ÷ 2 ]² = [ 16 ÷ 2 ]² = [ 13 ]² = 169

[(40 + 20) ÷ 2 ]² = [ 60 ÷ 2 ]² =  [ 30 ]² = 900

Option (A)900 is correct option.

Question #9

There are three figures in this problem. Every figure consists of three numbers one in the top of the figure and two numbers are in the bottom line. In every figure the number in the top of the figure is made up of remaining two numbers which are in the bottom line. The number in the top of the figure can be calculated by using any mathematical operations with the help of remaining two numbers. The mathematical operation we use to calculate the number in the 1st figure must be same in all the remaining two figures. 

Formula :-

Difference of squares of numbers in the two branches of given figure is equal to number in the top of the same figure. 

a² - b² = c (Number to be calculated) 

1st Figure

16² - 7² = 256 - 49 = 207

2nd Figure

12² - 8² = 144 - 64 = 80

3rd Figure

25² - 21² = 625 - 441 = 184 (The value of question mark) 

Option (2)184 is correct option.

 

Question #10

This maths reasoning questions consists of three figures and every figure have four numbers associated to it.  

          Two numbers are on the upper line of each box and two number are at the bottom line of each box.  Look at last figure , it have ? in its 3rd figure . So the solution of this problem is to find the value of question mark using three numbers associated to it . 

          But the main problem is how to utilised  these three numbers to get the value of question mark?

          Now watch carefully the 1st two figures . Since these figures have some big values of numbers in one box . 

          Now we have to find or search the  formula for these four numbers in 1st two figures to utilised them in any possible way to get number in that box . 

         The same formula will be applicable to third figure to find out the value of question mark.

1st Box 

Product of numbers in three small boxes is equal to number in 4th box 

4 × 3 × 2 = 24 

2nd Box 

Product of numbers in three small boxes is equal to number in 4th box 

(-2) × 2 × (-1) =  4

3rd Box 

Product of numbers in three small boxes is equal to number in 4th box 

0 × 6 × 5 = 0 ( The value of ?  ) 

Option (4)0  is correct option

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15 Questions Circle Problems 
 SSC CGL Reasoning

  Ten Most Important maths  Reasoning questions with answers for competitive exams in box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions. 

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